consider the reaction 2Fe(s)+3O2(g)-->Fe2O3 if 11.9g of iron III oxide is produc

Question

consider the reaction 2Fe(s)+3O2(g)-->Fe2O3 if 11.9g of iron III oxide is produced from a certain amount of iron how many grams of oxygen are needed for this reaction Please show work consider the reaction 2Fe(s)+3O2(g)-->Fe2O3 if 11.9g of iron III oxide is produced from a certain amount of iron how many grams of oxygen are needed for this reaction Please show work consider the reaction 2Fe(s)+3O2(g)-->Fe2O3 if 11.9g of iron III oxide is produced from a certain amount of iron how many grams of oxygen are needed for this reaction Please show work

Explanation / Answer

We can see from above that,

2 moles of Fe reacts with 3 moles of O2 to give 1 mole of Fe2O3

thus ratio of Fe2O3 to O2 is 1:3

moles of Fe2O3 = g/molar mass = 11.9 g / 159.69 g/mol = 0.07452 mols

so mols of O2 would be = 3 x 0.07452 = 0.224 mols

grams of O2 = 0.224 x 32 = 7.168 g of O2 are needed in this reaction

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