Cu (s) S (s) Cu 2S (s) Chem 101 Lab Expt 4 Formula of a Chemical Compound Set-Up

Question

Cu (s) S (s) Cu 2S (s) Chem 101 Lab Expt 4 Formula of a Chemical Compound Set-Up Data and Graphs: error (exp. data std)/std) 100% place data in Table 1-Synthesis of Cuprous Sulfide this column) Mass (g) crucible 11.8413 Mass (g) crucible copper 12.1712 (-2-1) 0.3299 Mass (g) copper Mass (g) crucible cuprous sulfide (at minimum mass) 12.2593 0.418 (4-1) Mass (g) cuprous sulfide 63.546 Molar mass (g/mole) of copper 10 7 32.065 Molar mass (g/mole) of sulfur Mass (g) sulfur (-53) 11 0.0881 0.0051915 (3/6) 12 Moles copper in cuprous sulfide 13 10 (-87) 0.0027475 Moles sulfur in cuprous sulfide (-910) 14 11 Molar ratio of copper to sulfur 0.0079391 xxx (3/5) 100) 15 12 copper in cuprous sulfide 16 13 Empirical formula of cuprous sulfide Cu type chem formula in 17 blank) 18 Graphs: (none) 19 20 Questions and Answers: (complete answers here and copy into Questions and Answers section) 21 Questions 1 & 2 are L (Pb) questions (not related to this Lab); Questions 3 & 4 are Copper (Cu) questions (related to this Lab)) ead 22 1) Write balanced equations for these Pb reactions. 23 put equation here) put equation here) 24 25 Molar masses: Pb 207.2 g/mol; O 5.9994 g/mol) 26 2) Percentage of lead in product 27 28 29 30 3) Why is the cuprous sulfide formula you calculated in this lab an empirical, and not a molecular formula? 31 32 answer here) 33 34 4) a) lfCu2S is weighed 0.002g low, what is Cu after adding this mass back? 35 36 4) b) State your recalculated molar ratio of copper to sulfur

Explanation / Answer

The molar ratio copper to Sulphur calculation is incorrect. The right is 1.88 which is about 2, that is what you should expect. Then the empirical formula is Cu2S.

3) it is empirical because express the minimal relationship between copper and sulphur atoms

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.