a Rb. on is 148 The radius of of pm. radius b) 148 pm a Rb atom would be c) 72 p

Question

a Rb. on is 148 The radius of of pm. radius b) 148 pm a Rb atom would be c) 72 pm The pm a 248 smallest ra Which of following has the 14. the b) K d) Mg2 a) K 15. Which of the following has the highest ionization energy b) O d) Ne a) S 3Brz 2CrBr3 if you start with 60 and the actual yield of CrBr3 is 3.0 moles, the yield is 16. In the reaction 2Cr moles of Br2 and excess Cr, b) 67% c) 75% d)90% a) 50% 17. An electron has the quantum numbers n 3:1 1 ml 0; ms +1/2. What orbita is the electron in? c) 3g b) 3d d) 2s e) none of th a) 3p Compared to nitrogen, the electron affinity of fluorine is 18. d) impossible c) greater b) smaller a) the same 19.The [Cl] in 0.30 M CaCl2 is c) M d) cannot be determined 0.15 b) 0.60 M a) 0.30 M 20. If 200 mL ofwater are added to 800 mLof 0.30 M Nacl, the final [Nac] is M d) 1.2 c) 0.30 M b) 0.24 M a) 0.20 M

Explanation / Answer

Q13) Correct answer is option a 248 pm

Because when the cation is formed then its radius decreases therefore the radius of the neutral atom is larger than its cation

Q14) Correct answer is option d that is Mg2+

Because as we move from left to right in the periodic table the atomic radius decreases and as we move from top to bottom then atomic radius increases. In the ionic radius as the cation formed then ionic radius decreases and when anion is formed radius increases.

Q15) correct answer is option d that Ne

Ne has highest ionization energy because it is nobel gas so its octets are complete so it do not loose electrons easily.

Q16) correct answer is option c

ecause mole ratio of the Br2 and CrBr3 is 3 : 2

So if we use 3.0 mol Br2 then it can form 6.0 mol Br2 * 2 mol CrBr3/3 mol Br2 = 4 mol CrBr3

Actual moles formed = 3.0

Therefore percent yield = (actual yield / theoretical yield )*100%

                                           = (3 mol / 4 mol )*100%

                                          = 75 %

Q17)correct answer is option a that is 3p orbital

N=3 means third energy level

And l = 1 means p orbital so the electron is in 3p orbital

Q18) correct answer is option c that is greater

Because F is more electronegative atom than nitrogen therefore it has greatest affinity towards electron.

Q19) correct answer is option b that is 0.60 M

Because 1 mol CaCl2 = 2 mol Cl-

Therefore [Cl-] = 2*[CaCl2]

                  [Cl-]= 2*0.30 M

                  [Cl-]=0.60 M

Q20) correct answer is option b that is 0.24 M

Because after adding 200 ml water total volume become 800+200 = 1000 ml

So we can calculate the molarity using the dilution formula

M1V1=M2v2

M2 = M1V1/V2

M2= 0.30 M *800 ml / 1000 ml

M2=0.24 M

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