The standardized NaOH solution was used to titrate vinegar samples. The vinegar
ID: 875652 • Letter: T
Question
The standardized NaOH solution was used to titrate vinegar samples. The vinegar was delivered from a 5.00 mL transfer pipet and diluted with water. The results of three titrations are given in the table below:
Concentration of NaOH= .1074
Pay close attention to the significant figures in the calculations involving the vinegar analysis!
What is the concentration of acetic acid determined in Run 1?
What is the concentration of acetic acid determined in Run 2?
What is the concentration of acetic acid determined in Run 3?
Concentration of NaOH=.1074 RUN 1 RUN 2 RUN 3 Volume of Vinegar (mL) 5.00 5.00 5.00 Volume of Water added (mL) 45.0 45.0 45.0 Initial NaOH Buret reading (mL) 1.21 3.76 4.03 Final NaOH Buret reading (mL) 18.14 20.56 21Explanation / Answer
Solution :- Given data
Molarity of the NaOH is given which is 0.1074 M
Volume of Vinegar used in each trial = 5.00 ml
Concnetration of vinegar = ?
Now lets calculate the volume of the NaOH solution needed for the each trial using the difference in the final and initial burette readings.
Volume of NaOH used in Run 1 = 18.14 ml
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.