The standard potentials of the following redox couples are given: E - (Ru 3+ ,Ru

Question

The standard potentials of the following redox couples are given: E-(Ru3+,Ru2+)=0.249V, E-(Ru2+,Ru+)=0.81V, E-(O2,H2O)=1.23V, E-(H+,H2)=0.00V. Answer the following and explain your answers using the relevant half reactions.

a. Predict if Ru2+ will be reduced by H2O at the standard condition.

b. Predict if Ru2+ will be oxidized by H2O at the standard condition.

c. Predict if Ru2+ will be oxidized by O2 in solution at the standard condition.

d. Predict if Ru2+ will be disproportionate at the standard condition

Explanation / Answer

From the given data for redox couple potentials, we can make the following conclusions:

1. The Ru2+ ion will neither oxidize nor reduce in Water.

2. Ru2+ ion will readily reduce O2, and will get oxidized to Ru3+ ion

3. Ru2+ reduces up to Ru(metallic), as well as Oxidises to Ru3+, i.e. gets disproportionated at standard conditions in an aqueous acid solution.

The above questions can be easily answered using these conclusions.

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