A wood burning stove was advertized as \"energy efficient\" by the manufacturer

Question

A wood burning stove was advertized as "energy efficient" by the manufacturer is used for one day in a 16.5 X 16.5 X 8.5 ft room with a ventilation rate of 0.5 ACH. After 18 hours the CO concentration in the room is 4 ppmv and stays at that level for the remaining 6 hours. Assume a room temperature and pressure of 10 degrees C and 1 atm, negligible concentrations of CO in the ventilation air and room initially, and a CO decay rate coefficient of 0.000006 s^-1. Determine the emission rate (in micrograms/s) of the wood burning stove.

Explanation / Answer

See emission rate is given by following equation

dN/N = -kdt

dN/4 = 0.000006 x 6

dN = 0.000144

dN/dt = 0.000144/18 = 8 x 10^-6 micrograms/s

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