help! Notice: Full credit given to 1 removed question estion 12 of 21 (1 point)

Question

help! Notice: Full credit given to 1 removed question estion 12 of 21 (1 point) Vermillion is a very rare and expensive solid natural to print the name chops on works of art. It is mercury (1l) sulfide (HgS), and it is also very insoluble in water. What is the maximum number of grams of vermilion you can make from the reaction of 50.0 mL of a 0.380 M aqueous solution of mercury (11) nitrate lHg(NOg with an excess ofa concentrated aqueous solution of sodium sufide (Na S)? known as Chinese red; it is the pigment used Number Check Ansver -Hint Progress11 124 Activity Grade: 22 Paints Possible Started: June 11 20 50 AM 10 percant ite

Explanation / Answer

Given data

50.0 ml of 0.380 M Hg(NO3)2

Excess Na2S

Mass of HgS = ?

Lets first write the balanced reaction equation

Hg(NO3)2(aq) + Na2S(aq) ----> HgS (s) + 2 NaNO3(aq)

Now using the molarity and volume of the Hg(NO3)2 calculate its moles

Formula to calculate moles is as follows

Molarity = moles/ volume in liter

Rearranging this formula we get

Moles = molarity * volume in liter

Moles og Hg(NO3)2 = 0.380 mol per L * 0.050 L                                      (50 ml = 0.050L)

                                     = 0.019 mol Hg(NO3)2

Now using the mole ratio of the Hg(NO3)2 and HgS calculate moles of HgS

From the balanced reaction equation the mole ratio of the Hg(NO3)2 and HgS is 1 :1

Therefore moles of HgS are same as moles of Hg(NO3)2

So moles of HgS = 0.019 mol HgS

Now lets convert moles of HgS to its mass

Mass = moles * molar mass

Molar mass of HgS = 232.66 g/mol

Lets put the values in the formula and calculate mass of HgS

Mass of HgS = 0.019 mol * 232.66 g per mol

                       = 4.42 g HgS

Mass of vermillion HgS = 4.42 g

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