In this experiment, the energy absorbed by the NO2 molecule is used for bond dis

Question

In this experiment, the energy absorbed by the NO2 molecule is used for bond dissociation, to produce NO(upsilon = 0.1) + O(3P), and the remaining energy is given to the translational motion of the two fragments. Since it takes less energy to form the NO (upsilon = 0) than the NO(upsilon = 1) state, the formation of NO(upsilon = 0) will corresponding to higher O atom velocity (actually, hegher velocities of both fragments). The energy of the O atom fragment corresponding to the peak at uO = 900 m s-1, EO = 1 /2 (0.016 kg mol-1 / 6.022 Times 10 23 mol-1) (900.00)2 at uO = 1400m s-1, EO = 1 / 2 mOuO2 = 1 / 2 (0.016 kg mol-1 / 6.022 Times 10 23 mol-1) (1400.00)2 = 2.6038 Times 10 -20 J. The energy of the NO molecule in upsilon = 0 state: E0 = 1 / 2 hcv0~ =1.855 Times 10 -20 J. upsilon = 1 state: E1 = 3 / 2 hcvo~ = 5.654 Times 10 -20 J. Since the total energy available to the fragments is Etot = hc(7400 cm-1) = 1.4651 Times 10-19 j, the translational energy available to the NO fragment (since rotational energy is zero), will be Etr(NO) = Etot - (E upsilon' + 1/2 mOuO2) and uNO = upsilon' = 1; uO = 900 m s-1 upsilon' = 0; uO = 1400 m s-1 Etr(NO) 7.921 Times 10-20 J 1.169 Times 10-19 J uNO 1783.0 m s-1 2166.0 m s-1

Explanation / Answer

you have to use the same equations and makes clearing the data requested

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.