In this experiment there is a box and a hanger, each of which is piled up with s

Question

In this experiment there is a box and a hanger, each of which is piled up with some masses. You'll be taking a series of acceleration measurements with different masses on the hanger, but you'll want to keep the total mass constant during this process.

Suppose: the box contains these masses: (100g, 50g, 10g) = a total of 160 grams, and on the hanger is hanging these masses: (200g, 20g, 20g) = a total of 240 grams. That's 400 grams of total load. Describe how you could transfer 40 grams from the box to the hanger, while keeping the total mass constant, using only the masses which are already present in the experiment. (Hint: you may need to move masses in both directions.)

I don't understand the question. What directions? I read the instructions and it mention that by transfeer 40 grams, it increase, is that correct? Please explain soon as possible. Thank you.

Theory: A free body diagram is presented below for a box being accelerated across a wooden board by a hanging mass. accelerates this way Figure 2: Free body diagram for a box being accelerated by a hanging mass. m,b = mass of the box, m,-mass of the hanging mass, N= Normal force, T= Tension in the string, f= frictional force Applying Newton's Second Law to each object. Solve for the acceleration of the system in terms of m mh, g, and MT Box Hanging mass = m,a (la, lb) F = mba X axis Y axis (2c) (2d) Substituting equation (2d) into (2a) gives T-ukmhg = mba Adding equation (2c) to equation 3 eliminates T and gives Where mT = m, t mb Solving for the acceleration of the system gives

Explanation / Answer

Take 50g and 10g masses from box and keep them in hanger.

then take 20g mass from hanger and keep it in box.

so, you are transfering 40g from box to hanger.

mass adding to the hanger,

50g + 10g - 20g = 40 grams

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