Part A Calculate the rate of the reaction when [N2 O5] = 5.5 x 10^-2 M Express y

Question

Part A Calculate the rate of the reaction when [N2 O5] = 5.5 x 10^-2 M Express your answer using two significant figures. Part B What would the rate of the reaction be at the same concentration as in part a if the reaction were second order? (Assume the same numerical value for the rate constar the appropriate units.) Express your answer using two significant figures. Rate 1.6 M/s The following reaction is first order in N2O5 : N2O5(g) right arrow NO3(g) + NO2(g) The rate constant for the reaction at a certain temperature is 0.053/s.

Explanation / Answer

A ) acc to the rate law for the first order reaction,

Rate=?d[A] / dt = k[A]1= k[A]

rate constant k =.053/s , [N2O5] = 5.5*10-2M

.053*5.5 * 10-2 = 2.9 * 10 -3 M/s

B ) not possible since th reaction depends on the concentration of one reactant only i.e.[N2O5]

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