Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a

Question

Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium iodide:

MnO4?(aq)+I?(aq)?MnO2(s)+I2(aq)

Since this reaction takes place in basic solution, H2O(l) and OH?(aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation:

MnO4?(aq)+I?(aq)+     ????MnO2(s)+I2(aq)+     ???

1. What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(l) and OH?(aq) in the blanks where appropriate. Your answer should have six terms.

Explanation / Answer

The reaction

MnO4?(aq)+I?(aq)?MnO2(s)+I2(aq)

Split in half cells

MnO4- = MnO2

I- = I2

balance I

MnO4- = MnO2

2I- = I2

balance O

MnO4- = MnO2 + H2O

2I- = I2

balance H

2H+ + MnO4- = MnO2 + H2O

2I- = I2

balance charges

e- + 2H+ + MnO4- = MnO2 + H2O

2I- = I2 + 2e-

balance e-

2e- + 4H+ + 2MnO4- = 2MnO2 + 2H2O

2I- = I2 + 2e-

add all

2I- + 2e- + 4H+ + 2MnO4- = 2MnO2 + 2H2O + I2 + 2e-

add all

2I- + 4H+ + 2MnO4- = 2MnO2 + 2H2O + I2

convert to OH-

4OH- + 2I- + 4H+ + 2MnO4- = 2MnO2 + 2H2O + I2 + 4OH-

add all

2I- + 4H2O + + 2MnO4- = 2MnO2 + I2 + 4OH-

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