Potassium chlorate is often used in oxygen generation systems, such as those in
ID: 1049793 • Letter: P
Question
Potassium chlorate is often used in oxygen generation systems, such as those in submarines. At high temperatures and in the presence of a catalyst (a substance that Increases the rate of a reaction without being consumed) potassium chlorate will decompose, with oxygen gas as one of the products. In this experiment, you will collect the oxygen from the decomposition of potassium chlorate and use it to calculate the mass percent of potassium chlorate in an unknown sample and the ideal gas constant R. The ideal gas constant links the temperature, pressure, volume, and number of moles of an ideal gas. The atoms of an ideal gas are infinitesimally small and experience negligible attractive forces. while oxygen is not an ideal gas, it is very close, so the ideal gas law does an excellent job of predicting its behavior. Write the balanced chemical equation for the decomposition of potassium chlorate that you will be observing in this experiment. Include states of matter. What is the purpose of the manganese (IV) oxide that is present in the unknown sample? What do you think would happen without it? One potential source of error stems from the fact that heat is applied to the test tube to initiate the reaction. Discuss why this might cause an error, and whether your calculated R will be too high or too low. If the water level within the gas collection bottle is higher than the water level in the trough, is the pressure in the bottle higher or lower than the atmospheric pressure? Why is it important to remove the latex tubing from the gas collection bottle after the decomposition is complete? A student measures out 2.050 g of sample. After the reaction, the residue has a mass of 1.673 g. What is the percent by mass of potassium chlorate in the sample?Explanation / Answer
Q1
KClO3(s) --> KCl(s) + 3/2O2(g)
Q2
MnO2 serves as a catalyst, it will favour the KCl(s) formation
if it is not present, it will not react
Q3
this might cause error since you may melt or add water vapor to the mix
Q4
if the level is higher, then the pressure is lower, since more pressure, pushes stronger, i.e. must decrease height
Q5
you need to remove it in order to get the total volume
Q6
m = 2.050 g of sample...
m = 1.673 g
find KClO3
MW of KCl = 74.5513 G/mol
mol of KCl = mass/MW = 1.673/74.5513 = 0.02244 mol of KCl
so..
mol fo KClO3 --> 0.02244
mass of KClO3 = 0.02244*122.55 = 2.75 g of KClO3
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