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a lead sample with a mass of 15.0g was immersed into a column of water with an i

ID: 863459 • Letter: A

Question

a lead sample with a mass of 15.0g was immersed into a column of water with an initial level of 45.0mL. Then an iron samle with a mass of 15.0g was also immersed into the same cylindeer. what is the new level of the column of water density after the lead and iron samples were added? Lead density = 11.3 g/cm^3 iron density = 7.86 g/cm^3
a lead sample with a mass of 15.0g was immersed into a column of water with an initial level of 45.0mL. Then an iron samle with a mass of 15.0g was also immersed into the same cylindeer. what is the new level of the column of water density after the lead and iron samples were added? Lead density = 11.3 g/cm^3 iron density = 7.86 g/cm^3
Lead density = 11.3 g/cm^3 iron density = 7.86 g/cm^3

Explanation / Answer

An object that sinks displaces an amount of fluid that's equal to the object's volume. Since we know the mass and density of the sinking object we can calculate its volume

Mass/volume = density

Volume=mass/ density

Mass of lead =15g,density=11.3g/cm3 volume displaced by lead sample =15g/11.3g/cm3

=1.32cm3  

New water level after adding lead sample =45.0+1.32 =46.32 ml

Mass of iron= 15g,density=7.86g/cm3 volume displaced by iron sample=15g/7.86g/cm3

  =1.90cm3

New water level after adding iron sample=46.32+1.90=48.22ml.

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