a krispy kreme original glazed doughnut weighs 52 g and contains 200 cal and 12

Question

a krispy kreme original glazed doughnut weighs 52 g and contains 200 cal and 12 g of fat. a)assuming that the fat in the doughnut is metabolized according to the given equation for tristearin, C57H110O6 (s) + 81.5 O2 (g) --> 57 CO2 (g) + 55 H2O (l)     -37760 kj/mol. calculate the number of calories in the reported 12 g of fat in each doughnut. b)If all the energy contained in a krispy kreme doughnut (and just in the fat) were transferred to 6.00 kg of water originally at 25.5 degrees C, what would be the final temperature of the water? c)When a krispy kreme apple fritter weighing 101 g is burned in a bomb calorimeter with Ccal = 95.3 kj/degrees C, the measured temperature increase is 16.7 degrees C. Calculate the number of calories in a krispy kreme apple fritter. d)What would the AH degree value be for the metabolism of 1 mole of the fat tristearin if the water produced by the reaction were gaseous instead of liquid?

Explanation / Answer

please use the proper upper- and lower-case letters for the elements in the compounds

C57H10O6 + 81.5O2 --> 57CO2 + 55H2O, ?H = -37760kJ/mole.....this seems extremely high
12g / 790g/mole = 0.015moles
37760kJ/mole x 0.015moles = 566.4kJ
1cal = 4.184J
1kcal = 4.184kJ
566.4kJ x 1kcal/4.184kJ x 1000cal/kcal = 1.35x10^5cal

if ?H = -37.76kJ/mole
37.76kJ/mole x 0.015moles = 0.566kJ
0.566kJ x 1kcal/4.184kJ x 1000cal/kcal = 135.37cal

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