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a https session masteringchemistry com/syet/itemwew assignmentProblemID 7370160 signed in as bryan tongl t Gibbs Free Energy. Spontaneity t Gibbs Free Energy: Spontaneity Elemental carbon usualy exists in one of two forms graphito or diamond. generally believed that diamonds astforever. The table showsthn standard enthapy or formation (AHrjandthe standard molarentnopy (S nvalues for diamond and grapnne Gibbs thee energy is a measure of the spontaneity It is the chemical poliential for a teacaon. Ahir (kJ/mol) S (J/mol K) minimized at equilibrum The change in Gbbs mee energy can be calculated by where AG, is the standard Gibbs tee energy change for a is the standard enthalpy change for a Part A reaction, Tis the temperature in kenins, and Asrm standard entropy change for a reaction What the stapdard Gbbsfree energy for the transformation of diamond graphie at208 K? For a reaction at equilbrium, AG m is equal to zero. For negative values, the reaction is spontanoous, and for posiive Express your answer to three significant figures and include the appropriate units. Submit Hints MAnswers Give Up Review Part Incorrect: Try Again: 3 attempts remaining Part B This queston wa be shown after you compete previous questionisi

Explanation / Answer

Cdaimond ------------> Cgraphite

Horxn = Hof of products - Hof of reactants

= Hof (graphite) - Hof (daimond)

= 0 - 1.897 kJ/mol

= -1.897 kJ/mol

= - 1897 J/mol

Sorxn = So (products) - So(reactants)

= So (graphite) - So(daimond)

= 5.74 J/K/mol - 2.38 J/K/mol

= 3.36 J/K/mol

-----------------------------------

Given that T = 298 K

Gorxn =Horxn - TSorxn

   = -1987 J/mol- (298 K) (3.36 J/K/mol)

= - 2988.3 J/mol

= -2.9 kJ

Therefore,

Gorxn =  -2.9 kJ

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