An aerosol spray can with a volume of 250 mLcontains 2.30 g of propane gas (C3H8

Question

An aerosol spray can with a volume of 250 mLcontains 2.30 g of propane gas (C3H8) as a propellant.

Part A

If the can is at 26?C, what is the pressure in the can?

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Part B

What volume would the propane occupy at STP?

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Part C

The can says that exposure to temperatures above 130 ?F may cause the can to burst. What is the pressure in the can at this temperature?

An aerosol spray can with a volume of 250 mLcontains 2.30 g of propane gas (C3H8) as a propellant.

Part A

If the can is at 26?C, what is the pressure in the can?

P = atm

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Part B

What volume would the propane occupy at STP?

V = L

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Part C

The can says that exposure to temperatures above 130 ?F may cause the can to burst. What is the pressure in the can at this temperature?

Explanation / Answer

A)
PV = nRT

P = (2.3/44)*0.0821*299/0.25
P = 5.13 atm.

B)

V = (2.3/44)*0.0821*298/1atm

V = 1.28 lt

C) 130 0F = 54 0C

P1/T1 = P2/V2

1 atm/298 = P2/327

P2 = 1.097 atn or 1.1 atm.

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