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I have a titration involving H2SO4 and Ba(OH)2. The equation is H2SO4 + Ba(OH)2

ID: 856679 • Letter: I

Question

I have a titration involving H2SO4 and Ba(OH)2. The equation is H2SO4 + Ba(OH)2 ---> BaSO4 + 2H2O.

After the equivalence point, more H2SO4 is added to increase the conductivity. What ions are responsible for this? I am confused as to whether H3O+ is a product of this reaction. BaSO4 is ionic, but my lab manual says that it is a precipitate (insoluble ionic compound) and that neither reaction product is significantly dissociated. This would mean that it isn't the one responsible for the conductivity, correct? So is H3O+ in play here? Can someone break all of this down for me? Does the above equation only apply to a situation where you're not going past the equivalence point?

Thanks so much!

Explanation / Answer

in this reaction BaSO4 is formed and precipitated. while add extra H2SO4 in the solution because of common ion effect BaSO4 will not dissociated. But here H3O+ and SO42- ions will be formed.

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