1. Assuming the following reaction proceeds in the forward direction, 3 Sn^4+(aq
ID: 856320 • Letter: 1
Question
1. Assuming the following reaction proceeds in the forward direction, 3 Sn^4+(aq) + 2 Cr(s) right arrow 3 Sn^2+(aq) + 2 Cr^3+(aq) a. Sn^4+(aq) is the reducing agent and Cr(s) is the oxidizing agent. b. Cr(s) is the reducing agent and Sn^2+(aq) is the oxidizing agent. c. Sn^2+(aq) is the reducing agent and Sn^2+(aq) is the oxidizing agent. d. Cr(s) is the reducing agent and Cr3+(aq) is the oxidizing agent. e. Cr(s) is the reducing agent and Sn^4+(aq) is the oxidizing agent. 2. The following reaction occurs spontaneously. 2 H^+(aq) + Ca(s) right arrow Ca^2+(aq) + H2(g) Write the balanced oxidatibn half-reaction. a. 2 H^+(aq) + 2 e^- right arrow H2(g) b. 2 H^+(aq) right arrow H2(g) + 2 e^- c. H2(g) right arrow 2 H^+(aq) + 2 e^- d. Ca(s) + 2 e^- right arrow Ca^2+(aq) e. Ca(s) right arrow Ca^2+(aq) + 2 e^-Explanation / Answer
1. e
Sn ^4+ undergoes reduction. So, that is oxidizing agent. Cr(s) undergoes oxidation. Hence, it is reducig agent.
2. e
The oxidation number of Ca increases from 0 on left side to +2 on right side.
So, it is oxidation.
the balanced oxidatin half reaction is option e.
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