2. If 3.0 g of CaCl2 are dissolved in 100 g of H2O what will the freezing point

Question

2. If 3.0 g of CaCl2 are dissolved in 100 g of H2O what will the freezing point of the solution be? The freezing point of pure water is 0 deg Celsius and Kf for water is 1.86 deg C m 0c. .50 c c) 1.50 Celsius d) -.50 Celsius e- 1.50 Celsius 2. If 3.0 g of CaCl2 are dissolved in 100 g of H2O what will the freezing point of the solution be? The freezing point of pure water is 0 deg Celsius and Kf for water is 1.86 deg C m 0c. .50 c c) 1.50 Celsius d) -.50 Celsius e- 1.50 Celsius 0c. .50 c c) 1.50 Celsius d) -.50 Celsius e- 1.50 Celsius

Explanation / Answer

Moles of CaCl2=3.0/111=0.027 mol

Molality of solution m=Moles of solute/mass of solution in kg

                                =0.027/0.100=0.27 m

Depression in freezing point=kf*m=1.86*0.27=0.05 C

Thus freezing point=0-0.05=-0.05 C

Hence d is correct option.

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