(a) How many grams of CaCl2 are needed to make 549.9 g of a solution that is 29.

Question

(a) How many grams of CaCl2 are needed to make 549.9 g of a solution that is 29.5% (m/m) calcium chloride in water? Note that mass is not technically the same thing as weight, but (m/m) has the same meaning as (w/w).

(a) How many grams of CaCl2 are needed to make 549.9 g of a solution that is 29.5% (m/m) calcium chloride in water? Note that mass is not technically the same thing as weight, but (m/m) has the same meaning as (w/w). Number g CaCl2 How many grams of water are needed to make this solution? Number g H2O (b) What is the volume percent % (v/v) of an alcohol solution made by dissolving 121 mL of isopropyl alcohol in 743 mL of water? (Assume that volumes are additive.) Number % (v/v) (c) The mass of solute per 100 mL of solution is abbreviated as % (m/v). (The abbreviation % (w/v) is also common.) How many grams of sucrose are needed to make 805 mL of a 38.0% (w/v) sucrose solution? Number g sucrose

Explanation / Answer

a) X g CaCl2 / 549.9 g solution = 29.5% / 100%

X / 549.9 = .295   X= 162.2 g CaCl2

549.9 g solution - 162.2 g CaCl2 = 387.8 g H2O

b) 121mL isoprophyl + 734mL H2O = 864 mL alcohol solution

121mL isoprophyl / 864mL solution = 0.14 x 100% = 14%

c) X g sucrose / 805mL solution = 38% / 100%

X= 305.9 g sucrose

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