(a) Given the following information: Rate = [Br-][C][H+]2 Give the order for eac
ID: 516639 • Letter: #
Question
(a) Given the following information: Rate = [Br-][C][H+]2 Give the order for each substance in the reaction. Give the overall order for the reaction. By what factor does the rate change for each of the following:
1) [Br-] is tripled
2)[C] is quadrupled
3)[H+] is halved
(b) Give the units of the rate constant if a reaction has each of the following overall orders and the reaction is measured in hours.
1) 3/2
2) 4th
(c) Give the overall reaction order that corresponds to a rate constant with each of the following units.
1) M^(5/2) min-1
2) sec-1
Explanation / Answer
a)
order of Br- = 1
order of C = 1
order of H+ = 2
overall order = 1 + 1 + 2 = 4
1) since order of Br- is 1 , tripling [Br-] will triple the reaction rate of reaction
Answer: 3 times
2) since order of C is 1 , quadrupling [C] will quadruple the reaction rate of reaction
Answer: 4 times
3) since order of H+ is 2 , halfing [H+] will make the reaction rate as 1/4 times
Answer: 1/4 times
b)
1) rate = k [A]^3/2
M/hr = k * M^3/2
k = M-1/2 . hr-1
Answer:
M-1/2 . hr-1
or
L1/2 mol-1/2 hr-1
2) rate = k [A]^4
M/hr = k * M^4
k = M-3 . hr-1
Answer:
M-3 . hr-1
or
L3 mol-3 hr-1
c)
1)
rate = k [A]
M/min = M^5/2 min-1 [A]
[A] = M^-3/2
order is -3/2
2)
rate = k [A]
M/s-1 = s-1 [A]
[A] = M
order is 1
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