A steel cylinder contains 1.50 g of ethanol vapor [C2H5OH(g)]. What is the press

Question

A steel cylinder contains 1.50 g of ethanol vapor [C2H5OH(g)]. What is the pressure of the vapor if the cylinder has a volume of 251mL and the temperature is 255 Celsius?
Please break down the problem step by step including formulas. A steel cylinder contains 1.50 g of ethanol vapor [C2H5OH(g)]. What is the pressure of the vapor if the cylinder has a volume of 251mL and the temperature is 255 Celsius?
Please break down the problem step by step including formulas.
Please break down the problem step by step including formulas.

Explanation / Answer

Moles ethanol = 1.50 g ( 1 mol/ 46.069 g/mol) = 0.0326

V = 0.251 dm^3
T = 255 + 273=528 K

p = nRT/V = 0.0326 x 0.08206 x 528 / 0.251 =5.6274 atm

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