Use valence bond theory to describe the bonding in the methylamine (CH3NH2) mole
ID: 854177 • Letter: U
Question
Use valence bond theory to describe the bonding in the methylamine (CH3NH2) molecule.
There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp3d orbitals. The electron-group geometries around C atom and the N atom are tetrahedral and trigonal bipyramidal, respectively. There are 6 sigma bonds and 1 pi bond in this molecule.
There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp3 orbitals. The electron-group geometries around C atom and the N atom are both tetrahedral. There are 6 sigma bonds and 0 pi bonds in this molecule.
A.There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp3d orbitals. The electron-group geometries around C atom and the N atom are tetrahedral and trigonal bipyramidal, respectively. There are 6 sigma bonds and 1 pi bond in this molecule.
B.There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp3 orbitals. The electron-group geometries around C atom and the N atom are both tetrahedral. There are 6 sigma bonds and 0 pi bonds in this molecule.
C. There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp2 orbitals. The electron-group geometries around C atom and the N atom are tetrahedral and trigonal planar, respectively. There are 6 sigma bonds and 0 pi bonds in this molecule.Explanation / Answer
B)There are two central atoms, C and N. The C atom is bound to three H atoms and to one N atom, whereas the N atom is bound to two H atoms and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the N atom's orbitals are hybridized as sp3 orbitals. The electron-group geometries around C atom and the N atom are both tetrahedral. There are 6 sigma bonds and 0 pi bonds in this molecule.
There is no pi bond N has a lone pair and hence sp3 orbitals
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