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Use valence bond theory to describe the number and types of hybrid bonding orbit

ID: 559833 • Letter: U

Question

Use valence bond theory to describe the number and types of hybrid bonding orbitals on the central atom of each of the following.

(a) BCl4

Type of hybridization: (pick one)

a. sp-hybridization

b. sp2-hybridization    

c. sp3-hybridization

d. sp3d-hybridization

e. sp3d2-hybridization

In BCl4, boron has ____ hybrid orbital(s).

(b)    ClF3
Type of hybridization: (pick one)

a. sp-hybridization

b. sp2-hybridization    

c. sp3-hybridization

d. sp3d-hybridization

e. sp3d2-hybridization


In ClF3, chlorine has _____ hybrid orbital(s).


(c)    CO2
type of hybridization: (pick one)

a. sp-hybridization

b. sp2-hybridization    

c. sp3-hybridization

d. sp3d-hybridization

e. sp3d2-hybridization


In CO2, carbon has _____ hybrid orbital(s).

Now, use the valence bond theory, to specify the type of hybridization on the central atom in the BH3 molecule.

a. sp-hybridization

b. sp2-hybridization    

c. sp3-hybridization

d. sp3d-hybridization

Draw orbital diagrams to show the distribution of the central atom's valence electrons before and after hybridization. (Complete each energy level from left to right. Enter __ for an unoccupied orbital, _ for a singly occupied orbital, and for a doubly occupied orbital.)

before hybridization

after hybridization

  
  
?? __ _
2s   
  
  
?? __ _
  
  
?? __ _
2p
  
?? __ _
  
  

Explanation / Answer

(A) BCl4- , the central atom Boron is sp3 hybridized
option c is the answer.
  In BCl4, boron has 4 hybrid orbitals

(B) ClF3, the central atom has sp3d hybridization
Option d) is the correct answer.
  In ClF3, chlorine has 5 hybrid orbitals

(C)In CO2 the carbon has sp hybridization, option a is the answer
  In CO2, carbon has 2 hybrid orbitals
BH3 , the central atom is sp2 hybridized

(D) Before hybridization : the configuration will be 1s22s2 2px1 2py1
   2s - both upward and downward arrow,
In 2p, 2px - one upward arrow and 2py - one upward arrow
After hybridization : the configuration will be 1s2 2s1 2px1 2py1 2pz1
2s - one upward arrow ; In 2p - 2px,2py,2pz one upward arrow each


  

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