1) calculate percent composition of P in Iron(II) phosphate (Fe3(PO4)2). 2) calc
ID: 853879 • Letter: 1
Question
1) calculate percent composition of P in Iron(II) phosphate (Fe3(PO4)2).2) calculate the wave length in (nm) for electromagnetic radiation that has a frequency equivalent to 9.84 x 10^15s-1. 1) calculate percent composition of P in Iron(II) phosphate (Fe3(PO4)2).
2) calculate the wave length in (nm) for electromagnetic radiation that has a frequency equivalent to 9.84 x 10^15s-1.
2) calculate the wave length in (nm) for electromagnetic radiation that has a frequency equivalent to 9.84 x 10^15s-1.
Explanation / Answer
1) % P = [ Number of parts by weight of P / Molar mass Fe3(PO4)2)] *100
Molar mass Fe3(PO4)2 = 3 * Fe + 2 *P + 8 *O = 3 *55.8 + 2 *30.9 + 8 *15.99
= 167.4 + 61.8 + 127.92 = 357.12
Number of parts by weight of P = 2 *P = 2*30.9 = 61.8
% P =( 61.8 / 357.12 ) *100 = 17.3% (answer)
2).wavelenght = velocity / frequency
Velocity = 3.0 *10^8 m/s
frequency = 9.84 x 10^15 s-1.
wavelenght = 3.0 *10^8 / 9.84 *10^15 = 0.305 *10^ -7
= 30.5 *10^-9 m = 30.5 nm (answer)
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