1) a) the momentum of a 2.5 mg mosquito traveling with a speed of 0.89 m/s. b)Ca

Question

1) a) the momentum of a 2.5 mg mosquito traveling with a speed of 0.89 m/s.

b)Calculate the momentum of a 3.4 g bullet traveling with a speed of 230 m/s.

c)Calculate the momentum of a 85 kg football player traveling with a speed of 6.9 m/s.

d)Calculate the momentum of a 850 kg car traveling with a speed of 79 km/h

2) A 95.6 kg halfback moving at 3.90 m/s on an apparent breakaway for a touchdown is tackled from behind. When he was tackled by an 81.6 kg cornerback running at 5.32 m/s in the same direction, what was their mutual speed immediately after the tackle?

3) A 9300 kg boxcar traveling at 14.7 m/s strikes a second boxcar at rest. The two stick together and move off with a speed of 5.20 m/s. What is the mass of the second car?

4) An atomic nucleus initially moving at 400 m/s emits an alpha particle in the direction of its velocity, and the new nucleus slows to 346 m/s. If the alpha particle has a mass of 2u and the original nucleus has a mass of 220u, what speed does the alpha particle have when it is emitted?

Explanation / Answer

1)
a) momentum = 2.5 * 10^-6 * 0.89 = 2.225 * 10^-6 kg m/se

b) momentum = 3.4 * 10^-3 * 230 = 0.782 kg m/sec

c) momentum = 0.085 * 6.9 = 0.5865 kg m/sec

d) 79 km/h = 79 * 5 /18 = 21.9444 m/sec

so.. momentum = 850 * 21.9444 = 18652.7778 kg m/sec


2) inital momentum = 95.6 * 3.9 + 81.6 * 5.32 = 806.952 m

let final velocity = v

so .. ( 95.6 + 81.6 )* v = 806.952

so final mutual vel = v = 4.5539 m/sec

3) intial momntum = 9300*14.7 = 136710
let mass of car = m

so ( 9300 + m)*5.32 = 136710
so m = 16397.3684 k g

4) intial momentum = 220u * 400 = 88000u
let final speed of alpha = v

final momentum = 218u*346 + 2u*v = 75428 u + 2v u

intial = final

75428 u + 2v u = 88000u
so v = 6286 m/sec

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