1) a hair 8 inches long. If the medulla is 60 % of the shaft and measures ~30 mi

Question

1) a hair 8 inches long. If the medulla is 60 % of the shaft and measures ~30 microns, what is the approximate total volume of the hair in m ^3?

2) it is needed 2.0 L HNO3 for your sample/test. If you have a micropipette with an outer diameter of 0.80mm and a wall thickness of 0.27 mm, to what height must you fill the capillary to obtain 2L?

3) Hexagon aquarium is filled up 10 cm from the table. Each side of the aquarium is 5.0 cm and the distance between 1 corner and the other directly across from it (going through the aquarium) is 10.0cm. The base of the base is 0.50 cm thick and the walls are 0.25cm thick. What is the volume of water contained in the aquarium?

Explanation / Answer

1. let the radius of the hair be r

then radisu of medulla = 0.6r ( 60 percent of shaft)

but 0.6r = 30 microns = 30*10^-6 m

so r = 50*10^-6 m

so length of hair = 8 inches = l = 0.2032 m

volume of hair = l*pi*r^2 = 0.2032*pi*(50*10^-6)^2 = 1.595*10^-9 m^3

now, 1 micro m ^3 = 10^-18 m^3

so VOlume V = 1.595*10^-9 m^3 = 1.595*10^9 micro m^3

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