Analysis of a Mixture of Carbonate and Bicarbonate Hi, I\'m doing the Analysis o

Question

Analysis of a Mixture of Carbonate and Bicarbonate

Hi, I'm doing the Analysis of a Mixture of Carbonate and Bicarbonate lab report.

During the lab, I did a titration to find the Total alkalinity, and a back titration, and the blank titration.

I got all the calculation for the first two titration, which is carbonate and dicarbonate, but I don't know how to calculate the calculation for the blank titration. Below is some of the information about the blank titration that i did:

Blank: Titrate w/ std. 0.1 M HCl mixture of 25 mL of water, 10 mL of 10% wt BaCl2 and 50.00 mL of std. 0.1 M NaOH. Repeat twice.

Here is my number after titrated:

trial 1: 49.8 mL of HCl used

trial2: 50.5 mL

trial 3: 50.2 mL

Now I need to calculate how much NaOH is consumed by barium chloride in the blank titration? I do know to find that value by subtracting the amount of HCl titrated with the blank solutionthat. But how do you do that. Can anyone help me with this? Thanks

Explanation / Answer

25 ml HCl WAS NUTRALISED BY 25 ML NaOH. REMAINIG NaOH IS 25 ML, NOW TO NURALISED THAT WE NEED

25 ML HCl BUT YOUR ONE OF THE BLANK VALUE IS 49.8

SO BaCl2 CONSUME NaOH IS 49.8-25 = 24.8

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