Analysis of a Mixture of Carbonate and Bicarbonate Hi, I\'m doing the Analysis o

Question

Analysis of a Mixture of Carbonate and Bicarbonate

Hi, I'm doing the Analysis of a Mixture of Carbonate and Bicarbonate lab report.

Below is the information background of my lab.

During the lab, I did a titration to find the Total alkalinity, and a back titration, and the blank titration.

I got all the calculation for the first two titration, which is carbonate and dicarbonate, but I don't know how to calculate the calculation for the blank titration. Below is some of the information about the blank titration that i did:

Blank: Titrate w/ std. 0.1 M HCl mixture of 25 mL of water, 10 mL of 10% wt BaCl2 and 50.00 mL of std. 0.1 M NaOH. Repeat twice.

Here is my number after titrated:

trial 1: 49.8 mL of HCl used

trial2: 50.5 mL

trial 3: 50.2 mL

Now I need to calculate how much NaOH is consumed by barium chloride in the blank titration? I do know to find that value by subtracting the amount of HCl titrated with the blank solutionthat. But how do you do that. Can anyone help me with this? Thanks

This procedure involves two titrations. First, total alkalinity (moles of bicarbonate + moles of carbonate) is measured by titrating the mixture with standard HCI to a methyl orange end point: HC03- + H+ H2CO3 C032- + 2H+ H2CO3 A separate aliquot of unknown is treated with excess standard NaOH to convert HCO3- to CO32-: HC03- + OH- CO32- + H2O Then all the carbonate is precipitated with BaCl2: Ba2+ + CO32- - BaCO3 (s) The excess NaOH is immediately titrated with standard HC1 to determine how much HCO3- was present. From the total alkalinity and moles of bicarbonate, you can calculate the original moles of carbonate present.

Explanation / Answer

To nutralised .1 molar 25 ml HCl 25 ml .1 molar NaOH is REQUIRE,

NOW 25 ml NaOH is remaining which you nutralised by HCl which 3 value you are given

your supose to get reading around 25 but since NaOH is consumed by barium chloride valu became say one of your valu 49.8.

so. 49.8 - 25 = 24.8 is volume of NaOH consume by bariumchoride

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.