If 14.4 moles of Cu and 16.2 moles of HNO3 are allowed to react, what is the max

Question

If 14.4 moles of Cu and 16.2 moles of HNO3 are allowed to react, what is the maximum number of moles of NO that can be produced? 3 Cu + 8 HNO3 ? 3Cu(NO3)2 + 2NO + 4H2O

If 14.5 moles of Cu and 44.8 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion?

3 Cu + 8 HNO3 ? 3Cu(NO3)2 + 2NO + 4H2O

When 15.3 g of aluminum (26.98 g/mol) reacts with 14.9 g of oxygen gas (32.00 g/mol), what is the maximum mass (in grams) of aluminum oxide (101.96 g/mol) that can be produced?

4 Al(s) + 3 O2(g) ? 2 Al2O3(s)

Explanation / Answer

4.04 mole of NO

6.13 moles of hno3 remain unreacted

28.9 grams of al2o3

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