If 0.050 mol of hydrochloric acid (HCl) is mixed with 0.050 mol of sodium hydrox

Question

If 0.050 mol of hydrochloric acid (HCl) is mixed with 0.050 mol of sodium hydroxide (NaOH) in a "coffee cup" calorimeter, the temperature of 50.0 g of the resulting solution increases from 25.0ºC to 31.5ºC. If the specific heat of the solution is 1.00 cal / g solution ºC, calculate the quantity of energy involved in the reaction. Also, is the reaction endothermic or exothermic?

Explanation / Answer

HCl + NaOH => NaCL + H2O Q = m*Cp*T = (50 g)*(1 cal/g)*(31.5C - 25 C) = 325calories reaction is exothermic, heat is released so temperatureincreases

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