Cup A Mass of cup and water: 59.49g Mass of sodium bicarb: 1.01g Mass of Citric

Question

Cup A

Mass of cup and water: 59.49g

Mass of sodium bicarb: 1.01g

Mass of Citric acid: 0.77g

Total mass: 61.27g

Mass of cup and solution after reaction: 58.52g

Mass of carbon dioxide?

Show your all work and use the correct number of significant figures and units.

The reaction of citric acid and sodium bicarbonate is written as
H3C6H5O7(aq) + 3 NaHCO3(aq) ? Na3C6H5O7(aq) + 3 H2O(l) + 3 CO2(g)

Part A: Equivalence Amounts

Plastic Cup A
1. Show that the equivalence amount of citric acid for 1.00 g of sodium bicarbonate is 0.76 g.
2. Calculate the theoretical yield of carbon dioxide from 1.00 g of sodium bicarbonate.
3. Calculate the percentage yield in the plastic cup A.

Plastic Cup B

Mass of cup and water: 58.96g

Mass of sodium bicarb: 2.00g

Mass of citric acid: 1.51g

Total Mass: 62.47

Mass of cup and solution: 57.81

Mass of carbon dioxide?

Plastic Cup B
4. Show that the equivalence amount of citric acid for 2.00 g of sodium bicarbonate is 1.52 g.
5. Calculate the theoretical yield of carbon dioxide from 2.00 g of sodium bicarbonate.
6. Calculate the percentage yield in the plastic cup B.

Plasic Cup C

Mass of cup and water: 59.61

Mass of sodium bicarbonate: 2.00g

Mass of citric acid: 0.77g

Total mass: 62.38g

Mass of the cup and solution: 61.67

Mass of carbon dioxide: 0.71g

Part B: Limiting Reactants
Plastic Cup C
7. Determine which reactant is the limiting reactant in the plastic cup C. Describe your reasoning.
8. Calculate the theoretical yield of carbon dioxide in the plastic cup C.
9. Calculate the percentage yield in the plastic cup C.

Plasic Cup D

Mass of the cup and water: 59.74g

Mass of sodium bicarb: 1.01g

Mass of citric acide: 1.51g

Total Mass: 62.26g

Mass of the cup and solution: 61.75g

Mass of carbon dioxide: 0.51g

Plastic Cup D
10. Determine which reactant is the limiting reactant in the plastic cup D. Describe your reasoning.
11. Calculate the theoretical yield of carbon dioxide in the plastic cup D.
12. Calculate the percentage yield in the plastic cup D.

13. Compare the percentage yield for four reactions. describe the differences and the similarities.

Please make writing and answers dark and clear! Thank you

Explanation / Answer

M.Wt of NaHCO3 = 84

M.Wt of citric acid = 192

now mole of NaHCO3 = wt /M.wt = 1/84 = 0.0119

since citric acid is a tri basic acid one mole of it requires 3 mole of NaOH

hence mole of citric acid = 0.0119/3 = 0.0039

now wt of citric acid = 0.004 * M.wt = 0.0039 * 192 = 0.76 g

Now NaHCO3 ---- > NaOH + CO2

its clear that one mole of NaHCO3 gives one mole of CO2

1 g NaHCO3 corresponds to 0.00119 mole of CO2

hence wt of CO2 = 0.0019 * M.wt of CO2 = 0.0019 * 44 = 0.523 g   

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