Se Express your answer in condensed form in order of increasing orbital energy a

Question

Se

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Zr

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Sb

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Explanation / Answer

1)

Number of electron in Se = 34

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4

Noble gas having lesser electron than Se and closest to it is Argon (Ar)

Number of electron in Ar = 18

electronic configuration of Ar is: 1s2 2s2 2p6 3s2 3p6

So, electronic configuration of Se in noble gas form is: [Ar] 3d10 4s2 4p4

Answer: [Kr]3d^104s^24p^4

2)

Number of electron in Zr = 40

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d2 5s2

Noble gas having lesser electron than Zr and closest to it is Krypton (Kr)

Number of electron in Kr = 36

electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

So, electronic configuration of Zr in noble gas form is: [Kr] 4d2 5s2

Answer: [Kr]4d^25s^2

3)

Number of electron in Sb = 51

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p3

Noble gas having lesser electron than Sb and closest to it is Krypton (Kr)

Number of electron in Kr = 36

electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

So, electronic configuration of Sb in noble gas form is: [Kr] 4d10 5s2 5p3

Answer: [Kr]4d^105s^25p^3

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.