Problem Situation: An equimolar liquid mixture F of benzene, toluene, and ethyl

Question

Problem Situation: An equimolar liquid mixture F of benzene, toluene, and ethyl benzene at high pressure is flashed continuously (steady-state) by expanding it to a low pressure into a flush drum resulting in two streams: a vapor V and a liquid L. The feed flow rate is 54,000 [mol/h]. The liquid composition is 14.2 % benzene, 30.6 % toluene, and 55.2 % ethylbenzene. The flow-rate ratio V/L is equal to 5.08. Requirements: Please, do the following: (a) Find the composition of the vapor stream coming out of the flash drum. (b) Determine the flow rates of both streams coming out of the flash drum, in [mol/h].

Explanation / Answer

b.

v+l= 54000

5.08L+L=54000

L= 54000/6.08== 8881.57895 mol/h

V=5* 8881.57895== 44407.8947 mol/h

a.

equimolar so,

moles of benzene, toluene, ethyl benzene all are same =54000/3= 18000 mol/h

moles of benzene in liquid=14.2*8881.57895/100== 1261.18421 mol/h

so moles of benzene in gas=18000-1261.18421== 16738.8158

moles of toluene in liquid=30.6*8881.57895/100= 2717.76316 mol/h

so moles of toluene in gas=18000-2717.76316= = 15282.2368

moles of ethyl benzene in liquid=55.2*8881.57895/100= 4902.63158 mol/h

so moles of ethyl benzene  in gas=18000-4902.63158= 13097.3684 mol/h

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