The following values may be useful when solving this tutorial. In the activity,

Question

The following values may be useful when solving this tutorial. In the activity, click on the E degree cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are The net reaction is Use the given standard reduction potentials in your calculation as appropriate. Express your answer numerically to three significant figures.

Explanation / Answer

Cu2+ + Ni => Cu + Ni2+

Eo(cell) = Eo(Cu2+/Cu) - Eo(Ni2+/Ni)

= 0.337 - (-0.257) = 0.594 V

Moles of electrons transferred n = 2

Delta Go = -RT ln Keq = -nFEo(cell)

Keq = exp(nFEo(cell)/RT)

= exp(2 x 96485 x 0.594/(8.314 x 298)

= 1.24 x 10^20 = 1.24 x 1020

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