This is the procedure : Into balloon number one, place one-fourth of a level tea

Question

This is the procedure :
Into balloon number one, place one-fourth of a level teaspoon of baking soda. Place one-half of a level teaspoon of baking soda in balloon number 2. Place three-fourths of a level teaspoon of baking soda in balloon number 3, and 1one level teaspoon of baking soda in balloon number 4.


These are the calculations:
Moles NaHCO3: One teaspoon of baking soda will have an approximate mass of 3.2 grams. From the molar mass of NaHCO3, determine and report the number of moles you have added to each balloon.

Moles of CH3COOH: The volume of 1 tablespoon is 15 mL. Therefore, 2 tablespoons of vinegar has a volume of 30 mL. White vinegar is approximately 5 percent CH3COOH. This means that you have added (0.05 x 30) 1.5 grams of acetic acid to each balloon. From the molar mass of CH3COOH, determine the number of moles of acetic acid you added to each balloon.

this is the second step

Measure 2 tablespoons of white vinegar and quickly pour it through the funnel into the balloon. Very quickly remove the funnel and tie off the balloon opening. Set this balloon aside.

Inside of the cells in column two, write in the mass and calculated moles of NaHCO3 for each of the four balloons. In column three, write in the the mass and calculated moles of CH3COOH you place in each balloon. In Column four, rank the volume of CO2 gathered in each balloon.

Write out the complete balanced equation for the reaction in the balloons.

Experiment Number Moles of NaHCO3 Moles of CH3COOH Rank of CO2 Produced Experiment 1 Experiment 2 Experiment 3 Experiment 4

Explanation / Answer

10 NaHCO3(s)     + 15 CH3COOH(aq) ? 20 CO2(g)      +10 NaCH3CO2(aq) + 2 H2O(l)

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