A 0.9182 g sample of CaBr2 is dissolved in enough water to give 500, ml of solut

Question

A 0.9182 g sample of CaBr2 is dissolved in enough water to give 500, ml of solution. What is the calcium ion concentration in this solution? 9.18 times 10 -3 M 2.30 times 10-3 M 2.72 times 10-3 4.59 times 10-3 M 1.25 times 10-3 M If 36.62 ml of 0.1510 M NaOH was needed to neutralize 50.0 ml of an H2SO4 what is the concentration of the original sulfuric acid solution? 0.00229 M 0.218 M 0.0523 M 0.209 M 0.105 M The pressure of a gas sample was measured to be 654 mmHg. What is the (1 atm = 1.01325 times 10 5 Pa) 87.2 kPa 118 kPa 6.63 times 10 4 kPa 8.72 times 10 4 kPa 8.72 times 10 7 kPa A smaple of a gass occupies 1.40 times 10 3 mL at 25 degree C and 760 mmHg. What occupy at the same temperature and 280 mmHg? 2,800mL 2,100mL 1,400mL 1,050mL 700mL The gas pressure in an aerosol can is 1.8 atm at 25 degree C. If the gas is an ideal gas pressure would develop in the can if it were heated to 475 degree C? 0.095 atm 0.72 atm 3.3 atm 4.5atm 34 atmA small bubble rises from the bottom of lake, where the temperature and 3.0 atm, to the water's surface, where the temperature is 25 degree C and the atm. Calculate the final volume of the bubble if its initial volume was 2.1 mL. 0.42 mL 6.2 mL 7.1mL 22.4 mL 41.4 mL If 0.820 mole of hydrogen gas has a volume of 2.00 L at a certain temperature and pressure What is the volume of 0.125 mol of this gas at the same temperature and pressure? 0.0512 L 0.250 L 0.305 L 4.01 L 19.5 L

Explanation / Answer

a)molar mass=199.89 g/mol

so number of moles=0.9182/199.89

=0.00459 moles

so conc.=0.00459*2

=9.19*10^-3

option A

9) let it be x.so,

2*x*50=34.62*0.151

or x=0.0523 M

option C

10)option A, 87.2 kPa

11)double of original volue.

so the correct option is A

12)1.8/(25+273)=P/(475+273)

or P=4.5 atm

so correct option is D

13)PV/T=constant

or 3*2.1/(273+4)=0.95*V/(25+273)

or V=7.1 mL

so the correct option is C

14)PV=nRT

or V/n=constant

or 2/0.82=V/0.125

or V=0.305 L

so the option is C

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