A 0.92 kg mass is attached to a light spring with a force constant of 33.9 N/m a
ID: 1293110 • Letter: A
Question
A 0.92 kg mass is attached to a light spring with a force constant of 33.9 N/m and set into oscillation on a horizontal frictionless surface. If the spring is stretched 5.0 cm and released from rest, determine the following.
(a) maximum speed of the oscillating mass
m/s
(b) speed of the oscillating mass when the spring is compressed 1.5 cm
m/s
(c) speed of the oscillating mass as it passes the point 1.5 cm from the equilibrium position
m/s
(d) value of x at which the speed of the oscillating mass is equal to one-half the maximum value
m
Explanation / Answer
a) 0.5*K*A^2 = 0.5*M*Vmax^2
Vmax = 0.3035 m/s
b) 0.5*k*x^2 + 0.5*m*v^2 = 0.5*K*A^2
k*x^2 + m*v^2 = k*A^2
(33.9*0.015*0.015)+(0.92*v^2) = (33.9*0.05*0.05)
= 0.2895 m/s
c) + 0.2895 m/s
d) 0.5*k*A/2^2 + 0.5*m*v^2 = 0.5*K*A^2
k*x^2 + m*v^2 = k*A^2
(33.9*0.025*0.025)+(0.92*v^2) = (33.9*0.05*0.05)
= 0.2628 m/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.