12. C+ 14.5 points I Previous Answers A key step in the metabolism of glucose fo
ID: 833051 • Letter: 1
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12. C+ 14.5 points I Previous Answers A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below G6P F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate AGO at 298 K 40V kJ/mol 1.67 (b) Calculate AG when 2, the CF6P]/CG6P] ratio, equals 14.0. 402 4.8 Your response differs from the correct answer by more than 10%. Double check your calculations. kJ/mol (c) Calculate AG when Q 0.800 40D 2.2 x Your response differs from the correct answer by more than 10%. Double check your calculations. kJ/mol (d) Calculate 2 in the cell if AG 3.10 kJ/mol. 6.88 Did you accidentally divide or take the inverse in your calculation?Explanation / Answer
K = 0.510, T = 298 K
(a) ?Go = -RT ln K
= -8.314 x 298 x ln(0.510) = 1668 J/mol ? 1.67 kJ/mol
(b) ?G = ?Go + RT ln Q
= 1668 + 8.314 x 298 x ln(14.0) = 8377 J/mol ? 8.21 kJ/mol
(c) ?G = ?Go + RT ln Q
= 1668 + 8.314 x 298 x ln(0.800) = 1115 J/mol ? 1.12 kJ/mol
(d) ?G = ?Go + RT ln Q
-3100 = 1668 + 8.314 x 298 x ln Q
ln Q = -1.925
Q = exp(-1.279) = 0.14595
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