1) In the photoelectric effect, a photon with an energy of 5.3 X 10^-19 J strike

Question

1) In the photoelectric effect, a photon with an energy of 5.3 X 10^-19 J strikes an electron in a metal. Of this energy, 3.6 X 10^-19 J is the minimum energy required for the electron to escape form the metal. The remaining energy appears as kinetic energry of the photoelectron. What is the velocity of the photoelectron, assuming it was initally at rest?

PLEASE SHOW WORK. STEP BY STEP please.

2) Which of the following frequencies of electromagentic raditaion has the shortest wavelenght?

a) 1 kilohertz

b) 1 terahertz

c) 1 dekahertz

d) 1 gigahertz

e) 1 megahertz

PLEASE EXPLAIN WHY

3) What is the molecular symmetry around the carbons in CCl2CH2 as predicited by VSEPR theory?

Explanation / Answer

(1) V = m/s^2 (insert your numbers and BAM you'll get it :)

(2) Know your pre-fixes

yottaY=1024=1 000 000 000 000 000 000 000 000zettaZ=1021=1 000 000 000 000 000 000 000exaE=1018=1 000 000 000 000 000 000petaP=1015=1 000 000 000 000 000teraT=1012=1 000 000 000 000gigaG=109=1 000 000 000megaM=106=1 000 000kilok=103=1 000hectoh=102=100*decada=101=10


100=1decid=10-1=0.1centic=10-2=0.01millim=10-3=0.001micro

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