Exp 1: [A] = 1M, [B] = 1M, Rate = 1M/s Exp 2: [A] = 1M, [B] = 2M, Rate = 1M/s Ex

ID: 831644 • Letter: E

Question

Exp 1: [A] = 1M, [B] = 1M, Rate = 1M/s

Exp 2: [A] = 1M, [B] = 2M, Rate = 1M/s

Exp 3: [A] = 2M, [B] = 1M, Rate = 4M/s

Rate=k[B]2

Use the following information to determine the rate law:

Exp 1: [A] = 1M, [B] = 1M, Rate = 1M/s

Exp 2: [A] = 1M, [B] = 2M, Rate = 2M/s

Exp 3: [A] = 2M, [B] = 1M, Rate = 1M/s

A. Rate = k[A] B. Rate=k[B] C. Rate=k[A][B] D. Rate=k[A]2[B] E. Rate=k[A][B]2 F. Rate=k[A]2[B]2 G. Rate=k[A]2 H.

Rate=k[B]2

Use the following information to determine the rate law:

Exp 1: [A] = 1M, [B] = 1M, Rate = 1M/s

Exp 2: [A] = 1M, [B] = 2M, Rate = 2M/s

Exp 3: [A] = 2M, [B] = 1M, Rate = 1M/s

A. Rate = k[A] B. Rate=k[B] C. Rate=k[A][B] D. Rate=k[A]2[B] E. Rate=k[A][B]2 F. Rate=k[A]2[B]2 G. Rate=k[A]2 H. Rate=k[B]2

from exp1 and exp2 whrn [A]is constant and [B] is doubled rate increases 4 times so rate w.r.t to B is [B]^2

from exp 1 and exp3 when [B] is constant and [A] is doubled rate aslo doubles

so rate w.r.t to A is [A]

so rate = k[A][B]^2

in the same way in second case rate = k[A][B]

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