Exp 16: Titrimetric Determination of KHP and Vinegar Samples 1. A titration of a

Question

Exp 16: Titrimetric Determination of KHP and Vinegar Samples

1. A titration of a 0.7871g sample potassium hydrogen phthalate, K 204.23 g/mole), required 21.22 mL of sodium hydroxide solution to reach the end point. What is the molarity sodium hydroxide solution. HP (GFW - 2. Three more samples of KHP (GFW 204.23 g/mole) weighing 0.8001g, 0.7001, and 0.7666g were titrated with the same sodium hydroxide solution. The volumes for the titrations were 21.55 mL, 17.44, and 18.37 mL respectively. alculate three more values for the molarity, then calculate the mean for all four measurements. 3. Test precision for these measurements. Can you reject any of the results using the "Q" test?

Explanation / Answer

Ans 1 :

The reaction involves equimolar concentration of both the reactants.

Number of moles of KHP = 0.7871 / 204.23 = 0.003854 moles

0.003854 = 0.02122 x M

M = 0.1816 M

So the molarity of sodium hydroxide solution is 0.1816 M

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