The equilibrium constant is 8.8 x 10 2 at a particular temperature for the react
ID: 830012 • Letter: T
Question
The equilibrium constant is 8.8 x 102 at a particular temperature for the reaction:
H2(g) + I2(g) ? 2HI(g)
Use this information to decide what will happen, given the following sets of initial conditions:
Will the reaction shift to the left, to the right or will the system be at equilibrium?
right left equilibrium PH2 = 0.47 torr, PI2 = 0.068 torr, PHI = 5.96 torr
right left equilibrium A 2.0 L flask contains 1.21 mol H2, 0.079 mol I2 and 8.39 mol HI.
right left equilibrium PH2 = 0.4875 torr,PI2 = 0.076 torr, PHI = 5.71 torr
right left equilibrium A 1.0 L flask contains 0.0450 mol H2, 0.011 mol I2 and 0.66 mol HI.
Explanation / Answer
(i) Phi^2/ Ph2 * Pi2 = 5.96^2/(.47*.068) =1111.43 > Kp =880
therfore reaction shifts to left.
ii) [8.39/2]^2/[1.21/2]*[.079/2] = 736.39 < Kc =880
reaction shifts to right
iii) 5.71^2/(.4875*.076) = 880.00 = Kp
it is in equillibrium
iv) [.66]^2/ ([.045][.011]) = 880 = Kc
it is in equillibrium
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