The quantity of antimony in a sample can be determined by an oxidation-reduction

Question

The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 9.79-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by 38.3 mL of a 0.145 M aqueous solution of KBrO3(aq). The unbalanced equation for the reaction is

BrO3- + Sb3+ ----> Br- +Sb5+

Calculate the amount of antimony in the sample and its percentage in the ore.

Explanation / Answer

here is the balanced equation

6H+(aq) + BrO3

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