%3Cp%20class%3D%22MsoNormal%20c2%22%3EWhich%20of%20the%20following%20would%20tec
ID: 827640 • Letter: #
Question
%3Cp%20class%3D%22MsoNormal%20c2%22%3EWhich%20of%20the%20following%20would%20techniques%0Awould%20be%20most%20appropriate%20to%20show%20that%20the%20diazonium%20reaction%20was%0Asuccessful%3F%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%20%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c4%22%3E%3Csup%3E1%3C%2Fsup%3EH%20%E2%80%93NMR%26nbsp%3B%26nbsp%3B%26nbsp%3B%20b.%0A%3Csup%3E13%3C%2Fsup%3EC-NMR%26nbsp%3B%26nbsp%3B%26nbsp%3B%20c.%20IR%26nbsp%3B%26nbsp%3B%26nbsp%3B%20d.%0AMS%26nbsp%3B%26nbsp%3B%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c4%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c2%22%3EWhy%20is%20it%20a%20bad%20idea%20to%20isolate%20a%20diazonium%0Asalt%3F%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c2%22%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%3Cspan%20class%3D%22c5%22%3EWhat%20is%20the%20main%20feature%0Aof%20azo-dyes%20that%20causes%20them%20to%20be%20colored%20compounds%3F%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c2%22%3E%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c2%22%3E%3Cspan%20class%3D%22c1%22%3E%26nbsp%3B%3C%2Fspan%3EThe%20reaction%0Ais%20driven%20forward%20by%20the%20formation%20of%20N%3Csub%3E2%3C%2Fsub%3E%20gas%20for%20two%0Areasons.%20Using%20the%20following%20equation%20(%3Cspan%20class%3D%22c6%22%3ED%3C%2Fspan%3EG%20%3D%0A%3Cspan%20class%3D%22c7%22%3ED%3C%2Fspan%3EH%20-%20T%3Cspan%20class%3D%22c6%22%3ED%3C%2Fspan%3ES)%2C%20explain%0Awhy%20%3Cspan%20class%3D%22c6%22%3ED%3C%2Fspan%3EG%20is%20negative%20for%20this%20reaction.%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c3%22%3E%26nbsp%3BUsing%20the%20equation%20for%0AK%3Csub%3Erxn%3C%2Fsub%3E%20%3D%20products%20%2F%20reactants%2C%20explain%20why%20the%20formation%0Aof%20N%3Csub%3E2%3C%2Fsub%3E%20causes%20the%20reaction%20to%20go%20forward.%26nbsp%3B%0A%26nbsp%3B%3C%2Fp%3E%0A%3Cp%20class%3D%22MsoNormal%20c4%22%3E%3C%2Fp%3E%0AExplanation / Answer
1)IR
2) because they are explosives
3)-N=N- gp
4)because Dh is -Ve and DS is +ve so we can obtain DG value is -ve
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