%253Cp%253Ewith%2520a%2526nbsp%253Btotal%2526nbsp%253Bcollisional%2526nbsp%253Bf
ID: 816954 • Letter: #
Question
%253Cp%253Ewith%2520a%2526nbsp%253Btotal%2526nbsp%253Bcollisional%2526nbsp%253Bfrequency%2526nbsp%253Bfor%2526nbsp%253BCO2%2526nbsp%253Bat%2526nbsp%253B1%2526nbsp%253Batm%2526nbsp%253Band%2526nbsp%253B327%2526nbsp%253BK%2526nbsp%253Bbeing%2526nbsp%253B7.34*10%255E34%2526nbsp%253Bm%255E-3%2526nbsp%253Bs%255E-1%252C%2526nbsp%253Bat%2526nbsp%253Bwhat%2526nbsp%253Btemperature%2526nbsp%253Bwould%2526nbsp%253Bthe%2526nbsp%253Btotal%2526nbsp%253Bcollisional%2526nbsp%253Bfrequency%2526nbsp%253Bbe%2526nbsp%253B13%2525%253C%252Fp%253EExplanation / Answer
collision frequency is prportional to square root of temperature
so, new temp Sqrt(T)=0.13*sqrt(327)
=>T=5.52 K
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