%3Cp%3E%3Cspan%20class%3D%22c1%22%3EA%20sample%20containing%20the%20following%20

Question

%3Cp%3E%3Cspan%20class%3D%22c1%22%3EA%20sample%20containing%20the%20following%20was%20prepared%3A%0A0.13%20M%20Pb%5E2%2B%20%2C%201.5%20%C3%97%2010-6%20M%20Pb%5E4%2B%20%2C%201.5%20%C3%97%2010-6%20M%20Mn%5E2%2B%20%2C%200.13%20M%0AMnO4%5E%E2%80%93%2C%20and%200.92%20M%20HNO3.%20For%20this%20sample%2C%20the%20following%20balanced%0Ahalf-reactions%20and%20net%20reaction%20can%20occur%3A%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cimg%20class%3D%22user-upload%22%20src%3D%0A%22http%3A%2F%2Fmedia.cheggcdn.com%2Fmedia%252Ffcf%252Ffcf9fc9f-36fd-4014-8ddd-d768c991d78b%252FphpMyJPfi.png%22%0Aheight%3D%22147%22%20width%3D%22563%22%20%2F%3E%3C%2Fp%3E%0A

Explanation / Answer

E0cell = Ecatode -Eanode

          = 1.69 - (-1.507)

         = 3.197 V

DG = -nFE0cell

DG = - 10*96500*3.197

DG = - 3085105 J or 3085.105 Kj

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