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Question

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Explanation / Answer

electric force is given by

F=K*Q1*Q2/d^2

Force between Q1 and Q3 is given by

F13=9*10^9*63*13/(5)

=1.47*10^12N direction of unit vector (2i+j/sqrt(5))

and force between Q2 and Q3 is

F23=9*10^9*33*13/(4)

=9.65*10^11N direction of unit vector (-j) (opp charges attract)

so net force =F13+F23=((14.7/sqrt(5))(2i+j)-9.65j)*10^11N

F=(13.14i-3.075j)*10^11N

Fx=13.14*10^11N

Fy=-3.075*10^11N

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