I am doing \"Sodium Borohydride Reduction of a Ketone \" I have to reduce Benzil

Question

I am doing "Sodium Borohydride Reduction of a Ketone"

I have to reduce Benzil (1,2 diphenyl ethanedione) to Hydrobenzion (1,2-diphenyl-1,2-ethanediol).

I am unsure how to calculate the limiting reagent. It said that it would be either the NaBH4 or the Benzil.

So far this is what i've gotten:

NaBH4: 50mg = 0.005g / 37.83g/mol = 0.000132 mol

Benzil: 180mg = 0.180g / 210.23g/mol = 0.000856 mol

i'm not sure what to do with those, or if i did it right, or if that is it or if i have to balance an equation or something.

Also i am unsure of how to calculate the theoretical yield of Hydrobenzion.

Thanks!!

Explanation / Answer

NaBH4 and benzil react in 1:1 ration

hence NaBH4 which is present in lesser quantity compared to others is limiting reagent.

hence moles of ydrobenzion depends on NaBH4 = 0.000132

hence theoretical yield = 0.000132 x 214.23 = 0.0283 gm

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