1.What is the equilibrium constant expression for the following reaction: PtCl 4

ID: 824933 • Letter: 1

Question

1.What is the equilibrium constant expression for the following reaction:

PtCl42?(aq)?Pt2+(aq) + 4Cl?(aq)

Choose from the list below and enter the letters alphabetical order. (e.g. For an equilibrium constant of [Cl-]4eq[Pt2+]eq enter AH.)

A) [Pt2+]eq B)[Cl-]eq C)[PtCl42-]eq D)[Pt2+]-1eq

E) [Cl-]-1eq F)[PtCl42-]-1eq G)[Pt2+]4eq H)[Cl-]4eq

I)[PtCl42-]4eq J)[Pt2+]-4eq K)[Cl-]4eq L)[PtCl42-]4eq

2.What is the equilibrium constant expression for the following reaction:

C5H5NH(aq) + H2O(l)?C5H5NH2+(aq)+OH?(aq)

Choose from the list below and enter the letters alphabetical order. (e.g. For an equilibrium constant of [OH-]-1eq[H2O]eq enter AH.)

A)[H2O]eq B)[C5H5NH]eq C) [C5H5NH2+]eq D[OH-]

E)[H2O]-1eq F) [C5H5NH]-1eq G) [C5H5NH2+]-1eq H)[OH-]-1eq

I)[PtCl42-]-4eq J)[Pt2+]-4eq K)[Cl-]-4 eq L)[PtCl42-]-4eq

1) the equilibrium constant is

K = [ Pt+2] [ Cl-] ^4 / [ PtCl4 ]

so the answer is

AHF

or AKF

as given both H and K options are same

2) the equilibrium constant is given by

K = [ C5H5NH2 +] [0H-] / [ C5H5NH]

H20 should be neglected .

so the answer is

CDF

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